string写时复制:将字符串str1赋值给str2后,除非str1的内容已经被改变,否则str2和str1共享内存。当str1被修改之后,stl才为str2开辟内存空间,并初始化。
#include#include #include #include using namespace std; void fun1() { string s1 = "hello, world!"; string s2 = s1; cout << "before: " << s2 << endl; char* ptr = const_cast (s1.c_str()); *ptr = 'f'; cout << "after: " << s2 << endl; } void fun2() { string s1 = "hello, world!"; string s2 = s1; cout << "before: " << s2 << endl; s1[0] = 'f'; cout << "after: " << s2 << endl; } int main() { cout << "fun1: " << endl; fun1(); cout << "fun2: " << endl; fun2(); return 0; }
注意:fun1中,通过char*修改s1行为,并不会触发stl的复制操作,因为stl并不认为通过char* 对s1的修改是对string s1的修改。