c 11并发之std::thread-ag真人游戏

构造函数如下：

default (1)
    thread() noexcept;
initialization(2)
    template  explicit thread (fn&& fn, args&&... args);
copy [deleted] (3)
    thread (const thread&) = delete;
move [4]
    thread (thread&& x) noexcept;

(1).默认构造函数，创建一个空的 thread 执行对象。
(2).初始化构造函数，创建一个 thread 对象，该 thread 对象可被 joinable，新产生的线程会调用 fn 函数，该函数的参数由 args 给出。
(3).拷贝构造函数（被禁用），意味着 thread 不可被拷贝构造。
(4).move 构造函数，move 构造函数，调用成功之后 x 不代表任何 thread 执行对象。
注意：可被 joinable 的 thread 对象必须在他们销毁之前被主线程 join 或者将其设置为 detached

#include  
#include 
#include 
using namespace std;  
void fun1(int n)  //初始化构造函数  
{  
   cout << "thread " << n << " executing\n";  
   n  = 10;  
   this_thread::sleep_for(chrono::milliseconds(10));  
}  
void fun2(int & n) //拷贝构造函数  
{  
    cout << "thread " << n << " executing\n";  
    n  = 20;  
    this_thread::sleep_for(chrono::milliseconds(10));  
}  
int main()  
{  
    int n = 0;  
    thread t1;               //t1不是一个thread  
    thread t2(fun1, n   1);  //按照值传递  
    t2.join();  
    cout << "n=" << n << '\n';  
    n = 10;  
    thread t3(fun2, ref(n)); //引用  
    thread t4(move(t3));     //t4执行t3，t3不是thread  
    t4.join();  
    cout << "n=" << n << '\n';  
    system("pause");
    return 0;  
} 

view code

#include 
#include
#include
#include 
using namespace std;
void running()
{
    cout << "thread is running..." << endl;
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    // 栈上
    thread t1(running); // 根据函数初始化执行
    thread t2(running);
    thread t3(running);
    // 线程数组
    thread th[3] {thread(running), thread(running), thread(running)}; // 执行
    // 堆上
    thread* pt1(new thread(running));
    thread* pt2(new thread(running));
    thread* pt3(new thread(running));
    // 线程指针数组
    thread* pth(new thread[3]{thread(running), thread(running), thread(running)});
    return a.exec();
}

多线程传递参数

#include 
#include
#include
#include 
using namespace std;
void running(const char* str,const int id)
{
    cout << "thread" << id << "is running..."<< str << endl;
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    // 栈上
    thread t1(running,"hello1",1); // 根据函数初始化执行
    thread t2(running,"hello2",2);
    thread t3(running,"hello3",3);
    return a.exec();
}

join

join 是让当前主线程等待所有的子线程执行完，才能退出。

#include 
#include
#include
#include 
using namespace std;
void running(const char* str,const int id)
{
    cout << "thread" << id << "is running..."<< str << endl;
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    // 栈上
    thread t1(running,"hello1",1); // 根据函数初始化执行
    thread t2(running,"hello2",2);
    thread t3(running,"hello3",3);
    cout << t1.joinable() << endl;
    cout << t2.joinable() << endl;
    cout << t3.joinable() << endl;
    t1.join(); // 主线程等待当前线程执行完成再退出
    t2.join();
    t3.join();
    return a.exec();
}

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detach

线程 detach 脱离主线程的绑定，主线程挂了，子线程不报错，子线程执行完自动退出。 线程 detach以后，子线程会成为孤儿线程，线程之间将无法通信。 

#include 
#include
#include
#include 
using namespace std;
void running(const char* str,const int id)
{
    cout << "thread" << id << "is running..."<< str << endl;
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    // 栈上
    thread t1(running,"hello1",1); // 根据函数初始化执行
    thread t2(running,"hello2",2);
    thread t3(running,"hello3",3);
    cout << t1.joinable() << endl;
    cout << t2.joinable() << endl;
    cout << t3.joinable() << endl;
    t1.detach();
    t2.detach();
    t3.detach();
    return a.exec();
}

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获取cpu核心个数

#include 
#include
#include
#include 
using namespace std;
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    auto n = thread::hardware_concurrency();//获取cpu核心个数
    cout << n << endl; # 4
    return a.exec();
}

cpp原子变量与线程安全。

#include 
#include
#include
#include 
using namespace std;
const int n = 1000000;
int num = 0;
void run()
{
    for (int i = 0; i < n;   i){
        num  ;
    }
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    clock_t start = clock();
    thread t1(run);
    thread t2(run);
    t1.join();
    t2.join();
    clock_t end = clock();
    cout << "num=" << num << ",spend time:" << end - start << "ms" << endl;
    return a.exec();
}

运行结果：num=1157261,spend time:9ms
结果并不是200000，这是由于线程之间的冲突

互斥量

#include 
#include
#include
#include 
#include 
using namespace std;
const int n = 1000000;
int num = 0;
mutex m;
void run()
{
    m.lock();
    for (int i = 0; i < n;   i){
        num  ;
    }
    m.unlock();
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    clock_t start = clock();
    thread t1(run);
    thread t2(run);
    t1.join();
    t2.join();
    clock_t end = clock();
    cout << "num=" << num << ",spend time:" << end - start << "ms" << endl;
    return a.exec();
}

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运行结果：num=2000000,spend time:5ms

原子变量。

#include 
#include
#include
#include 
#include 
using namespace std;
const int n = 1000000;
atomic_int num {0}; // 不会发生线程冲突，线程安全
void run()
{
    for (int i = 0; i < n;   i){
        num  ;
    }
}
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    clock_t start = clock();
    thread t1(run);
    thread t2(run);
    t1.join();
    t2.join();
    clock_t end = clock();
    cout << "num=" << num << ",spend time:" << end - start << "ms" << endl;
    return a.exec();
}

c 11 并发之std::atomic。

lambda与多线程

#include 
#include
#include
#include 
#include 
using namespace std;
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    auto fun = [](const char* str){cout << str << endl;};
    thread t1(fun,"hello world");
    thread t2(fun,"hello c  ");
    return a.exec();
}

时间等待相关

#include 
#include
#include
#include 
#include 
using namespace std;
int main(int argc, char *argv[])
{
    qcoreapplication a(argc, argv);
    auto fun = [](const char* str){
        this_thread::sleep_for(chrono::seconds(1));
        this_thread::yield();// 让cpu执行其他空闲线程
        cout << this_thread::get_id() << endl;
        cout << str << endl;
    };
    thread t1(fun,"hello world");
    return a.exec();
}